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21 October, 20:23

In a titration of HCl with NaOH, 100mL of the base was required to neutralize 20mL of 5.0 M HCl. What is the molarity of the NaOH?

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  1. 21 October, 20:44
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    1 M

    Explanation:

    Step 1:

    Data obtained from the question. This includes the following:

    Volume of base (Vb) = 100mL

    Volume of ac (Va) = 20mL

    Molarity of acid (Ma) = 5M

    Molarity of base (Mb) = ... ?

    Step 2:

    The balanced equation for the reaction. This is given below:

    HCl + NaOH - > NaCl + H2O

    From the above equation, the following were obtained:

    Mole ratio of the acid (nA) = 1

    Mole ratio of the base (nB) = 1

    Step 3:

    Determination of the molarity of the base.

    The molarity of the base can be obtained as follow:

    MaVa/MbVb = nA/nB

    5 x 20 / Mb x 100 = 1

    Cross multiply to express in linear form

    Mb x 100 = 5 x 20

    Divide both side by 100

    Mb = (5 x 20) / 100

    Mb = 1 M

    Therefore, the molarity of the base is 1 M
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