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14 October, 22:55

What is the empirical formula of a substance that consists of 0.910 g calcium, 0.636 g nitrogen, and 1.453 g oxygen?

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  1. 14 October, 23:18
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    You need to change them to mole

    mole = mass / Molar mass

    mole of Ca = 0.910 g / 40.08 g/mol = 0.0227 mol

    mole of N = 0.636 g / 14.01 g/mol = 0.04539 mol

    mole of O = 1.453 g / 16.00 g/mol = 0.0908 mol

    Then, take the smallest number and divide for all number (in mol that I just found)

    Ca = 0.0227 / 0.0227 = 1

    N = 0.04539 / 0.0227 = 1.9999 (round it 2)

    O = 0.0908 / 0.0227 = 4

    So the empirical formula will be Ca1N2O4 (CaN2O4)
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