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23 September, 06:41

suppose that 0.05 g of NaHCO3 reacts with 0.05 g of HCI and the reaction bubbles due to the carbon dioxide being produced. if the substance produced are 0.04 g water and 0.03g of salt how many grams if carbon dioxide gas were produced

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  1. 23 September, 06:57
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    The balanced chemical equation for the given reaction:

    NaHCO₃ + HCl - -> NaCl + H₂O + CO₂

    Given, mass of NaHCO₃ = 0.05 g

    Molar mass of NaHCO₃ = 84.007 g/mol

    Moles = mass/molar mass

    Moles of NaHCO₃ = 0.05 g/84.007 g/mol

    Moles of NaHCO₃ = 6.0 x 10⁻⁴

    Given, mass of HCl = 0.05 g

    Molar mass of HCl = 36.46 g/mol

    Moles of HCl = 0.05 g / 36.46 g/mol

    Moles of HCl = 1.4 x 10⁻³

    Since NaHCO3 has the least number of moles, it is the limiting reagent.

    As per the balanced equation the molar ratio between NaHCO₃ : CO₂ is 1:1

    Therefore, moles of CO₂ = 6.0 x 10⁻⁴

    Molar mass of CO₂ = 44 g/mol

    Mass = moles x molar mass

    Mass of CO₂ = 6.0 x 10⁻⁴ mol x 44 g/mol = 0.0264 g

    Mass of carbon dioxide gas produced = 0.0264 g
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