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30 August, 07:53

A chemist has a sample of hydrated Li2SiF6 and it weighs 0.4813 grams. He heats it strongly to drive off the water of hydration, and after heating, he found that the anhydrous compound has a mass of 0.391 grams. What is the percent of water in the hydrate?

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Answers (2)
  1. 30 August, 09:26
    0
    18.8%

    Explanation:

    Step 1:

    The following data were obtained from the question.

    Mass of hydrated Li2SiF6 = 0.4813 g

    Mass of anhydrous Li2SiF6 = 0.391 g

    Step 2:

    Determination of the mass of the water in the hydrate.

    Mass of water = (Mass of hydrated Li2SiF6) - (Mass of anhydrous Li2SiF6)

    Mass of water = 0.4813 - 0.391

    Mass of water = 0.0903 g

    Step 3:

    Determination of the percentage of water in the hydrate.

    The percentage of water = Mass of water / mass of hydrate x 100

    The percentage of water = 0.0903/0.4813 x 100

    The percentage of water = 18.8%
  2. 30 August, 09:46
    0
    percentage of water = 18.76%

    Explanation:

    A chemist has a sample of hydrated Li2SiF6 and it weighs 0.4813 grams.

    The overall weight of the compound is 0.4813 grams.

    weight of hydrated sample = 0.4813 grams.

    weight of anhydrous compound = 0.391 grams

    percentage weight of water = mass of water/mass of the hydrated compound * 100

    mass of water = mass of hydrated compound - mass of anhydrous compound

    mass of water = 0.4813 - 0.391 = 0.0903 grams.

    percentage of water = 0.0903/0.4813 * 100

    percentage of water = 9.03/0.4813

    percentage of water = 18.761687097

    percentage of water = 18.76%
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