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21 November, 20:58

To prepare a solution of BF4 - (aq), HF (g) is bubbled into a solution containing 50.0 g of H3BO3 in a 1 L reaction vessel. Calculate the maximum number of moles of BF4 - (aq) that can be produced.

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  1. 21 November, 22:57
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    The chemical reaction involved is as follows

    H₃BO₃ + 4HF = HBF₄ + 3H₂O

    1 mol 1 mol

    mol weight of H₃BO₃ is 61.84 gm

    50g = 50 / 61.84 mol.

    = 0.8 mol.

    .8 mol of H₃BO₃ will form. 8 mol of BF₄⁻ ion.
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