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22 July, 10:46

What is the percentage yield when 2.0g of ethene, c2h4, is formed from 5g of ethanol, c2h5oh

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Answers (2)
  1. 22 July, 12:20
    0
    The percentage yield of the reaction is 65.8 %

    Explanation:

    Step 1: Data given

    Mass of ethene (C2H4) = 2.0 grams

    Molar mass ethene = 28.05 g/mol

    Mass of ethanol formed (C2H5OH) = 5.0 grams

    Molar mass of ethanol = 46.07 g/mol

    Step 2: The balanced equation

    C2H5OH (aq) → C2H4 (g) + H2O (l)

    Step 3: Calculate moles ethene

    Moles ethanol = mass ethanol / molar mass ethanol

    Moles ethanol = 5.0 grams / 46.07 g/mol

    Moles ethanol = 0.1085 moles

    Step 4: Calculate moles ethene

    For 1 mol ethanol we'll have 1 mol ethene and 1 mol H2O

    For 0.1085 moles we'll have 0.1085 moles ethene

    Step 5: Calculate mass ethene

    Mass ethene = 0.1085 moles * 28.05 g/mol

    Mass ethene = 3.04 grams

    Step 6: Calculate percent yield of the reaction

    % yield = (actual mass / theoretical mass) * 100 %

    % yield = (2.0 grams / 3.04 grams) * 100 %

    % yield = 65.8 %

    The percentage yield of the reaction is 65.8 %
  2. 22 July, 14:30
    0
    65.8%

    Explanation:

    First we'll begin by writing a balanced equation for for the production of C2H4 from C2H5OH.

    When ethanol (C2H5OH) undergoes dehydration, it will produce ethene (C2H4) according to the equation given below:

    C2H5OH - > C2H4 + H2O

    Now, from the balanced equation above, we can obtain the theoretical yield of ethene as follow:

    Molar Mass of C2H5OH = (12x2) + (5x1) + 16 + 1 = 24 + 5 + 16 + 1 = 46g/mol

    Molar Mass of C2H4 = (12x2) + (4x1) = 24 + 4 = 28g/mol

    From the balanced equation above,

    46g of C2H5OH produced 28g of C2H4.

    Therefore, 5g of C2H5OH will produce = (5x28) / 46 = 3.04g

    Therefore, the theoretical yield of C2H4 is 3.04g

    From the question, the actual yield of C2H4 is 2g

    With the above information, we can easily find the percentage yield as follow

    %yield = Actual yield / Theoretical yield x100

    %yield = 2/3.04 x100

    % yield = 65.8%

    Therefore, the percentage yield of C2H4 is 65.8%
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