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18 December, 10:35

What volume of a 6.84M sodium bromide solution would be needed to make 588mL of a 1.84m solution by dilution

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  1. 18 December, 11:58
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    The initial volume is 158mL

    C1V1=C2V2

    V1+C2V2/C1 = 0.588Lx1.84 M / 6.84 M = 0.158L = 158mL
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