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31 December, 02:39

Find the number of bromine molecules present in 2.25 mol.

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  1. 31 December, 04:22
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    Answer is: the number of bromine molecules is 1.35·10²⁴.

    n (Br₂) = 2.25 mol; amount of bromine molecules.

    Na = 6.022·10²³ mol⁻¹; Avogadro constant.

    N (Br₂) = n (Br₂) · Na.

    N (Br₂) = 2.25 mol · 6.022·10²³ mol⁻¹.

    N (Br₂) = 13.54 ·10²³.

    N (Br₂) = 1.35·10²⁴; number of bromine molecules.
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