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4 December, 12:39

Perhatikan persamaan termokimia berikut.

HCl (aq) + NaOH (aq) - > NaCl (aq) + H2O (l). delta H=-54 kJ

a. Gambarlah diagram tingkat energi untuk reaksi tersebut

b. Berapakah perubahan entalpi jika 100 mL NaOH 1 M?

c. Berapakah perubahan entalpi jika 10 mL HCl 1 M direaksikan dengan 20 mL NaOH 1 M?

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Answers (1)
  1. 4 December, 13:48
    0
    the reaction is

    HCl (aq) + NaOH (aq) - > NaCl (aq) + H2O (l).

    the enthalpy of reaction is H=-54 kJ

    Which means that one mole of HCl reacts with one mole of NaOH and gives 54 kJ of energy / heat

    The reaction is exothermic and the graph will be like as shown in figure (1)

    The question is

    What is the enthalpy change if 10 mL HCl 1 M is reacted with 20 mL 1 M NaOH?

    Moles of HCl = molarity X volume = 1 M X 10 mL = 10 mmoles

    moles of NaOH reacted = moles of NaOH

    so total moles of acid base reacted = 10mmoles = water formed

    when one mole of acid base reacted to give one mole of H2O

    so when 10mmole of water are formed energy released is = 54 X 10 X 10^-3 = 0.54 kJ

    reaksinya

    HCl (aq) + NaOH (aq) - > NaCl (aq) + H2O (l).

    entalpi reaksi adalah H = - 54 kJ

    Yang berarti satu mol HCl bereaksi dengan satu mol NaOH dan memberikan 54 kJ energi / panas

    Reaksinya eksotermik dan grafiknya akan seperti yang ditunjukkan pada gambar (1)

    Pertanyaannya adalah

    Apa perubahan entalpi jika 10 mL HCl 1 M direaksikan dengan 20 mL 1 M NaOH?

    Moles HCl = molaritas X volume = 1 M X 10 mL = 10 mmoles

    Tahi lalat NaOH bereaksi = mol NaOH

    sehingga jumlah mol asam basa bereaksi = 10mmol = air terbentuk

    ketika satu mol asam basa bereaksi untuk memberikan satu mol H2O

    jadi ketika 10mmole air terbentuk, energi yang dilepaskan adalah = 54 X 10 X 10 ^ - 3 = 0,54 kJ
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