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8 October, 07:03

What volume (mL) of 7.48x10 - 2 M phosphoric acid can be completely reacted with 115 mL of. 244 M sodium

hydroxide? Hint: balance equation

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Answers (1)
  1. 8 October, 10:58
    0
    Answer:125ml - volume of phosphoic acid

    Explanation:

    The equation of the reaction is

    H3PO4 + 3 NaOH - --> Na3PO4 + 3H2O

    Such that I mole of H3PO4 reacts with 3 moles of NaOH to produce the products above.

    Given that

    M1 = Molarity of phosphoric acid = 7.48x10^-2 M

    n1 = number of moles of phosphoric acid = 1

    V1=? ml

    M2 = Molarity of Sodium hydroxide = 0.244 M

    V2 = volume of sodium hydroxide = 115ml

    n2=number of moles of sodium hydroxide = 3

    Using the Dilution equation formulae,

    M1V1/n1 = M2V2/n2

    7.48X10-2 x V1 / 1 = 0.244M x 115ml/3

    V1=0.244Mx115mlx1/0.0748M X 3

    V1 = 28.06/0.2244 = 125.04ml

    V1=125.04ml rounded up to 125ml
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