Calculate the number of grams of Fe that are produced when 57 grams of FeO is reacted with excess aluminum in the following reaction: 2Al (s) + 3FeO (s) - > 3Fe (s) + Al₂O₃ (s)

Mass of Fe produced = 44.7 g

Explanation:

Given dа ta:

Mass of Fe produced in gram = ?

Mass of FeO react = 57 g

Solution:

Chemical equation:

2Al + 3FeO → 3Fe + Al₂O₃

Number of moles of FeO:

Number of moles = mass / molar mass

Number of moles = 57 g / 71.844 g/mol

Number of moles = 0.8 mol

Now we will compare the moles of Fe with FeO from balance chemical equation.

FeO : Fe

3 : 3

0.8 : 0.8

Mass of Fe:

Mass = Mass * molar mass

Mass = 0.8 mol * 55.845 g/mol

Mass = 44.7 g