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4 July, 20:09

How many grams of NaCL are required to prepare 50ml of a 2.0 molar solution

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  1. 4 July, 23:26
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    5.85 gm.

    Explanation:

    We know that,

    Normality = Molarity * Molecular weight

    Equivalent weight

    Since molecular weight of NaCl = equivalent weight = 23+35.5 = 58.5

    Normality of NaCl = molarity=2

    Now,

    Normality = weight in gram * 1000

    Volume * equivalent weight

    Weight in gram is given by,

    =Normality * Volume * equivalent weight

    1000

    = 2 * 50 * 58.5

    1000

    =5.85 gm.
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