How many grams of NaCL are required to prepare 50ml of a 2.0 molar solution

5.85 gm.

Explanation:

We know that,

Normality = Molarity * Molecular weight

Equivalent weight

Since molecular weight of NaCl = equivalent weight = 23+35.5 = 58.5

Normality of NaCl = molarity=2

Now,

Normality = weight in gram * 1000

Volume * equivalent weight

Weight in gram is given by,

=Normality * Volume * equivalent weight

1000

= 2 * 50 * 58.5

1000

=5.85 gm.