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31 July, 06:23

What is the molarity of a saline solution that contains 0.900 g NaCl (58.44 g/mol) dissolved in 100.0 mL of solution?

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  1. 31 July, 08:58
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    The molarity of a saline solution that contain 0.900 g NaCl (58.44 g/mol) dissolved in 100.0 ml solution is 0.15 M

    calculation

    Molarity = moles / volume in liters

    volume in liters = 100.0 ml / 1000 = 0.1 L

    moles = mass: molar mass

    = 0.900 g : 58.44 g/mol = 0.015 moles

    molarity is therefore = 0.015 moles / 0.1 L = 0.15 M
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