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27 December, 17:31

A 2.00 L bottle of Dr Pepper contains 225 g of sucrose, C12H22O11. What is the molality of that solution?

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  1. 27 December, 17:58
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    Molality = 0.33 mol/Kg

    Explanation:

    Given dа ta:

    Volume of solvent = 2.00 L

    Mass of solute = 225 g

    Molality of solution = ?

    Solution:

    Formula:

    Molality = Number of moles of solute / kg of solvent

    Now we will calculate the moles of solute.

    Number of moles = mass / molar mass

    Number of moles = 225 g / 342.3 g/mol

    Number of moles = 0.66 mol

    Now we will calculate the Kg of solvent.

    1 L = 1 Kg

    2 L = 2 Kg

    Molality = Number of moles of solute / kg of solvent

    Molality = 0.66 mol / 2 kg

    Molality = 0.33 mol/Kg
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