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28 October, 19:11

If 13.5 moles of oxygen are reacted with an excess of ammonia, how many moles of NO and of H2O are formes given the following equation. 4NH3+5O2 = 4NO + 6H2O

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  1. 28 October, 22:23
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    NO=10.8Mol

    H2O=16.2Mol

    4NH3 + 5O2 - -> 4NO + 6H2O

    5Mol of O2 Produce 4Mol of NO

    Therefore 13.5Mol of O2 produce NO = (13.5/5) x4 = 10.8

    H2O Mol = (13.5/5) x 6 = 16.2
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