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3 October, 15:46

A canister of 2.00 moles of helium has a volume of 30.0 L and is at a temperature of 293 Kelvin. what is the pressure of this gas?

1. 19.5 kPa

2. 101.3 kPa

3. 162 kPa

4. 211 kPa

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Answers (1)
  1. 3 October, 16:33
    0
    P = 162 KPa

    Explanation:

    Given dа ta:

    Number of moles = 2 mol

    Volume of gas = 30.0 L

    Temperature of gas = 293 K

    Pressure of gas = ?

    Solution:

    The given problem will be solve by using general gas equation,

    PV = nRT

    P = Pressure

    V = volume

    n = number of moles

    R = general gas constant = 0.0821 atm. L / mol. K

    T = temperature in kelvin

    P = nRT/V

    P = 2 mol * 0.0821 atm. L / mol. K * 293 K / 30.0 L

    P = 48.11 atm. L / 30.0 L

    P = 1.6 atm

    atm to kelvin:

    1.6*101 = 162 KPa
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