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15 March, 14:41

2 NH3 + 2 O2 → N2O + 3 H2O If 80.0 grams of O2 are reacted in the above reaction, how many grams of N2O will be produced (MM O2=32 g/mol; NH3=17.04 g. mol, N2O=44.02 g/mol, H2O=18.02 g/mol) ?

29.1 g

67.6 g

55.0 g

165 g

+2
Answers (1)
  1. 15 March, 15:08
    0
    2 NH3 + 2 O2 → N2O + 3 H2O

    mass of O2 = 80.0g

    moles of O2 = 80.0/32 = 2.5 moles O2

    moles of N2O = 2.5 moles O2 x 1 mole N2O = 1.25 moles N2O

    2 moles of O2

    mass of N2O produced;

    moles = mass/Molar mass

    mass = moles x Molar mass

    = 1.25 x 44.02

    = 55.025 g N2O

    55.025g of N2O is produced in this reaction.
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