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11 August, 06:57

Consider the following reaction: NO (g) + SO 3 (g) ⇌ NO 2 (g) + SO 2 (g) A reaction mixture initially contains 0.86 atm NO and 0.86 atm SO 3. Determine the equilibrium pressure of NO 2 if K p for the reaction at this temperature is 0.0118. 0.048 atm 0.012 atm 0.85 atm 0.084 atm 0.78 atm

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  1. 11 August, 10:44
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    The equilibrium pressure of NO2 is 0.084 atm

    Explanation:

    Step 1: Data given

    A reaction mixture initially contains 0.86 atm NO and 0.86 atm SO3.

    Kp = 0.0118

    Step 2: The balanced equation

    NO (g) + SO3 (g) ⇌ NO2 (g) + SO2 (g)

    Step 3: The initial pressures

    p (NO) = 0.86 atm

    p (SO3) = 0.86 atm

    p (NO2) = 0 atm

    p (SO2) = 0 atm

    Step 4: The pressure at the equilibrium

    For 1 mol NO we need 1 mol SO3 to produce 1 mol NO2 and 1 mol SO2

    p (NO) = 0.86 - x atm

    p (SO3) = 0.86 - xatm

    p (NO2) = x atm

    p (SO2) = x atm

    Step 5: Define Kp

    Kp = ((pNO2) * (pSO2)) / ((pNO) * (pSO3))

    Kp = 0.0118 = x² / (0.86 - x) ²

    X = 0.08427

    p (NO) = 0.86 - 0.08427 = 0.77573 atm

    p (SO3) = 0.86 - 0.08427 = 0.77573 atm

    p (NO2) = 0.08427 atm

    p (SO2) = 0.08427 atm

    The equilibrium pressure of NO2 is 0.08427 atm ≈ 0.084 atm
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