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28 November, 21:26

6) What is the molality of 0.4 moles of KCl in 1500 g of solvent?

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Answers (1)
  1. 29 November, 00:53
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    Molality = 0.267 mol/Kg

    Explanation:

    Given dа ta:

    Moles of KCl = 0.4 mol

    Mass of solvent = 1500 g

    Molality of solution = ?

    Solution:

    Formula:

    Molality = moles of solute / kg of solvent

    Now we will convert the g into kg.

    1500 g * 1kg / 1000 g

    1.5 kg

    Now we will put the values in formula.

    Molality = 0.4 mol / 1.5 kg

    Molality = 0.267 mol/Kg
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