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28 October, 12:10

6. If 0.500 mol NaN3 react, what mass in grams of nitrogen will result?

2 NaN3 → 2 Na + 3 N2

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  1. 28 October, 12:47
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    21 g of N₂ are produced by the decomposition

    Explanation:

    The reaction is: 2 NaN3 → 2 Na + 3 N2

    2 moles of sodium nitride decompose in order to produce 2 moles of Na and 3 moles of nitrogen gas.

    According to stoichiometry, ratio is 2:3. Therefore we say,

    2 moles of nitride can produce 3 moles of N₂

    Then, 0.5 moles of NaN₃ will produce (0.5. 3) / 2 = 0.75 moles of N₂

    We convert the moles to mass, to find the answer

    0.75 mol. 28 g / 1 mol = 21 g
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