How many moles of gas molecules will be present in 5000 L of air at STP?

5000L • 1 mole / 22.4L so approximately 223 moles

n = 223 mol

Explanation:

Given data

P = 1.00 atm (standard pressure)

T = 273.15 K (standard temperature)

n = ?

R = 0.08206 atm. L/mol. K (ideal gas constant)

V = 5000 L

We can find the moles of gas molecules using the ideal gas equation.

P * V = n * R * T

1.00 atm * 5000 L = n * (0.08206 atm. L/mol. K) * 273.15 K

n = 223 mol