Which is the correct equilibrium constant expression for the following reaction? Fe2O3 (s) + 3H2 (g) - -> 2Fe (s) + 3H2O (g) Kc = [Fe2O3] [H2]3/[Fe]2[H2O] Kc = [Fe]2[H2O]3/[Fe2O3] [H2]3 Kc = [H2]/[H2O] Kc = [H2O]3/[H2]3 Kc = [Fe] [H2O]/[Fe2O3] [H2]

Question

Chemistry

Jocelyn

12 September, 02:28

Which is the correct equilibrium constant expression for the following reaction? Fe2O3 (s) + 3H2 (g) - -> 2Fe (s) + 3H2O (g) Kc = [Fe2O3] [H2]3/[Fe]2[H2O] Kc = [Fe]2[H2O]3/[Fe2O3] [H2]3 Kc = [H2]/[H2O] Kc = [H2O]3/[H2]3 Kc = [Fe] [H2O]/[Fe2O3] [H2]

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Answers (1)

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Shania Osborn · Answer 1

The equilibrium constant Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³

Explanation:

Step 1: Data given

For the reaction aA + bB ⇆ cC + dD

the equilibrium constant Kc = [C]^c * [D]^d/[B]^b*[A]^a

Step 2: The balanced equation

Fe2O3 (s) + 3H2 (g) - -> 2Fe (s) + 3H2O (g)

Step 3: Calculate the equilibrium constant Kc

Kc = [C]^c * [D]^d/[B]^b*[A]^a

⇒with [C] = [Fe]

⇒ with c = 2

⇒with [D] = [H2O]

⇒with d = 3

⇒with [A] = [Fe2O3]

⇒with a = 1

⇒with [B] = [H2]

⇒with b = 3

Kc = [C]^c * [D]^d/[B]^b*[A]^a

Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³

The equilibrium constant Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³