Ask Question
25 June, 05:29

How many grams of K2CO3 are needed to prepare a 400.0 mL of a 4.25M solution?

1.7 g

235 g

81.3 g

138 g

+5
Answers (1)
  1. 25 June, 06:49
    0
    235 g

    Explanation:

    From the question;

    Volume is 400.0 mL Molarity of a solution is 4.25 M

    We need to determine the mass of the solute K₂CO₃,

    we know that;

    Molarity = Number of moles : Volume

    Therefore;

    First we determine the number of moles of the solute;

    Moles = Molarity * volume

    Moles of K₂CO₃ = 4.25 M * 0.4 L

    = 1.7 moles

    Secondly, we determine the mass of K₂CO₃,

    We know that;

    Mass = Moles * Molar mass

    Molar mass of K₂CO₃, is 138.205 g/mol

    Therefore;

    Mass = 1.7 moles * 138.205 g/mol

    = 234.9485 g

    = 235 g

    Thus, the mass of K₂CO₃ needed is 235 g
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How many grams of K2CO3 are needed to prepare a 400.0 mL of a 4.25M solution? 1.7 g 235 g 81.3 g 138 g ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers