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16 January, 07:03

What is the molarity of a solution that contains 1.2 moles of calcium carbonate (CaCO3) in 1.22 liters of solution? Round to the nearest hundreth.

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  1. 16 January, 08:17
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    The molarity of this CaCO3 solution is 0.98 M

    Explanation:

    Step 1: Data given

    Number of moles calcium carbonate (CaCO3) = 1.2 moles

    Volume of the solution = 1.22 L

    Step 2: Calculate the molarity of this CaCO3 solution

    Molarity = moles / volume

    Molarity CaCO3 solution = moles CaCO3 / volume of the solution

    Molarity CaCO3 solution = 1.2 moles CaCO3 / 1.22 L

    Molarity CaCO3 solution = 0.98 mol/L = 0.98 M

    The molarity of this CaCO3 solution is 0.98 M
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