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22 June, 16:59

If the oxide contains 7.17 % O by mass, what is the identity of the metal?

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  1. 22 June, 17:37
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    Answer is: the identity of the metal is lead (Pb).

    ω (O) = 7.17% : 100%.

    ω (O) = 0.0717; mass percentage of oxygen in the oxide.

    If we take 100 grams of compound:

    1) m (O) = ω (O) · 100 g.

    m (O) = 0.0717 · 100 g.

    m (O) = 7.17 g; mass of oxygen in the oxide.

    n (O) = m (O) : M (O).

    n (O) = 7.17 g : 16 g/mol,

    n (O) = 0.448 mol; amount of oxygen.

    2) m (M) = 100 g - 7.17 g.

    m (M) = 92.83 g; mass of metal in the oxide.

    n (O) = n (M) = 0.448 mol.

    M (M) = m (M) : n (M).

    M (M) = 92.83 g : 0.448 mol.

    M (M) = 207.20 g/mol; molar mass of the metal.
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