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21 November, 13:41

Calculate the moles of calcium chloride (CaCl2) needed to react in order to produce 85.00 grams of calcium carbonate (CaCO3). use the balanced equation!

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Answers (2)
  1. 21 November, 16:28
    0
    We need 94.3 grams of CaCl2

    Explanation:

    Step 1: Data given

    Mass of Calciumcarbonate (CaCO3) = 85.00 gram

    Molar mass CaCO3 = 100.09 g/mol

    Molar mass of CaCl2 = 110.98 g/mol

    Step 2: The balanced equation

    CaCl2 + CO2 + H2O → CaCO3 + 2HCl

    Step 3: Calculate moles CaCO3 produced

    Moles CaCO3 = mass CaCO3 / molar mass CaCO3

    Moles CaCO3 = 85.00 grams / 100.09 g/mol

    Moles CaCO3 = 0.850 moles

    Step 4: Calculate moles CaCl2

    For 1 mol CaCl2 we need 1 mol CO2 and 1 mol H2O to produce 1 mol CaCO3 and 2 moles HCl

    For 0.850 moles CaCO3 we need 0.850 moles CaCl2

    Step 5: Calculate mass CaCl2

    Mass CaCl2 = moles CaCl2 * molar mass CaCl2

    Mass CaCl2 = 0.850 moles * 110.98 g/mol

    Mass CaCl2 = 94.3 grams

    We need 94.3 grams of CaCl2
  2. 21 November, 17:32
    0
    0.85 mole

    Explanation:

    Step 1:

    The balanced equation for the reaction of CaCl2 to produce CaCO3. This is illustrated below:

    When CaCl2 react with Na2CO3, CaCO3 is produced according to the balanced equation:

    CaCl2 + Na2CO3 - > CaCO3 + 2NaCl

    Step 2:

    Conversion of 85g of CaCO3 to mole. This is illustrated below:

    Molar Mass of CaCO3 = 40 + 12 + (16x3) = 40 + 12 + 48 = 100g/mol

    Mass of CaCO3 = 85g

    Moles of CaCO3 = ?

    Number of mole = Mass / Molar Mass

    Mole of CaCO3 = 85/100

    Mole of caco = 0.85 mole

    Step 3:

    Determination of the number of mole of CaCl2 needed to produce 85g (i. e 0. 85 mole) of CaCO3.

    This is illustrated below:

    From the balanced equation above,

    1 mole of CaCl2 reacted to produced 1 mole of CaCO3.

    Therefore, 0.85 mole of CaCl2 will also react to produce 0.85 mole of CaCO3.

    From the calculations made above, 0.85 mole of CaCl2 is needed to produce 85g of CaCO3
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