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27 February, 11:11

A sample of oxygen gas has a volume of 27.3 mL at 294 K. At what temperature would the gas have a volume of 40.0 mL

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  1. 27 February, 13:46
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    Using Gay Lussac's Law, you would have:

    27.3mL/294K = 40.0mL/x. where x is the temperature in Kelvin it would have at 40.0mL

    Solving for x you get, 431 Kelvin.
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