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5 November, 12:45

At a certain temperature the rate of this reaction is first order in HI with a rate constant of : 7.21s?12HI (g) ? H2 (g) + I2 (g)

Suppose a vessel contains HI at a concentration of 0.440M

Calculate the concentration of HI in the vessel 0.210 seconds later. You may assume no other reaction is important.

Round your answer to 2 significant digits.

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  1. 5 November, 15:04
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    [HI] = 0.097 M

    Explanation:

    Let's consider the following reaction.

    2 HI (g) ⇄ H₂ (g) + I₂ (g)

    The order of reaction for HI is 1. Thus, we can calculate the concentration of HI ([HI]) at certain time using the following expression:

    ln [HI] = ln [HI]₀ - k. t

    where,

    [HI]₀ is the initial concentration of HI

    k is the rate constant

    t is the time elapsed

    When [HI]₀ = 0.440 M and t = 0.210 s, the concentration of HI is

    ln [HI] = ln (0.440) - 7.21 s⁻¹ * 0.210 s

    ln [HI] = - 2.33

    [HI] = 0.097 M
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