Aluminum foil is often incorrectly termed tin foil. If the density of tin is 7.28g/cm³, what is the thickness of a piece of tin foil that measures 10.0cm by 10.0cm and has a mass of 1.091g?

15.0 µm

Step-by-step explanation:

Density = mass/volume

D = m/V Multiply each side by V

DV = m Divide each side by D

V = m/D

dа ta:

m = 1.091 g

D = 7.28 g/cm³

l = 10.0 cm

w = 10.0 cm

Calculation:

(a) Volume of foil

V = 1.091 g * (1 cm³/7.28 g)

= 0.1499 cm³

(b) Thickness of foil

The foil is a rectangular solid.

V = lwh Divide each side by lw

h = V / (lw)

= 0.1499 / (10 * 10)

= 1.50 * 10⁻³ cm Convert to millimetres

= 0.015 mm Convert to micrometres

= 15.0 µm

The foil is 15.0 µm thick.