rinking water suggest an upper limit of 250 mg/L for chloride ion. If 1.03*104 liters of water in a storage tank contains 1.40 grams of Cl-, what is the contaminant level in ppm? in ppb? Is this level acceptable based on EPA guidelines?

Question

Chemistry

Dalia Zhang

5 February, 19:16

rinking water suggest an upper limit of 250 mg/L for chloride ion. If 1.03*104 liters of water in a storage tank contains 1.40 grams of Cl-, what is the contaminant level in ppm? in ppb? Is this level acceptable based on EPA guidelines?

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Answers (1)

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Paul · Answer 1

This water has a level acceptable, 0.1359ppm and 135.9ppb.

Explanation:

1.40g of Cl⁻ are:

1.40g Cl⁻ * (1000mg / 1g) = 1400mg Cl⁻

In 1.03x10⁴L:

1400mg / 1.03x10⁴L = 0.1359mg/L.

As the upper limit of Cl⁻ in water is 250mg/L, this water has a level acceptable

ppm are the ratio between mg of solute and liters of solution, that means the tank contains 0.1359mg/L = 0.1359ppm

ppb, parts per billion are 1000 times ppm, thus, parts per billion of the storage tank are:

0.1359ppm * 1000 = 135.9ppb