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6 October, 19:50

A balloon of air now occupies 5.0 L, at 25 celcius and 1.00 atm. What temperature was it initially, if it occupied 4.0 L and was in a very cold freezer with a pressure of 0.92 atm?

combined gas laws

A. 219k B. 298k C. 325k D. 425k

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  1. 6 October, 21:02
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    Answer: A. 219K

    Explanation:

    Using the Combined Gas Law; P1 V1/T1 = P2V2/T2

    Where P1 = 0.92 atm, P2 = 1.00 atm

    V1 = 4.0 L, V2 = 5.0 L

    T1 = ?, T2 = 25 celcius = 298K

    We therefore make T1 the subject of the formular;

    T1 = P1. V1. T2 / P2. V2

    = 0.92atm x 4.0L x 298K / 1.00 atm x 5.0 L

    = 1096.64 / 5

    = 219.328 approx 219K
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