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18 August, 19:17

How many grams of C3H8 would be needed to produce 6.39 grams of CO2?

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  1. 18 August, 20:50
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    2.13g

    Explanation:

    Atomic mass of CO2 = 12 + 32 = 44g/Mol

    Atomic mass of C3H8 = 36 + 8 = 44g/Mol

    Reaction

    C3H8 + 5O2 - -> 3CO2 + 4H2O

    3CO2 = 6.39g

    Required C3H8 = (6.39 / (44 x 3)) x 44 = 2.13g
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