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24 June, 13:04

The Ksp for Cu (OH) 2 is 4.8 * 10-20. Determine the molar solubility of Cu (OH) 2 in a buffer solution with a pH of 10.1.

A) 6.0 * 10-10

B) 7.6

C) 2.2 * 10-10

D) 3.8 * 10-16

E) 3.0 * 10-12

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  1. 24 June, 15:02
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    E) 3.0x10⁻¹²

    Explanation:

    Ksp of Cu (OH) ₂ is defined as:

    Cu (OH) ₂ (s) ⇄ Cu²⁺ (aq) + 2 OH⁻ (aq)

    Ksp = [Cu²⁺] [OH⁻]²

    When pH is 10.1, [OH⁻] is:

    pOH = 14 - pH

    pOH = 3.9

    pOH = - log [OH⁻]

    [OH⁻] = 1.26x10⁻⁴M

    Replacing in ksp formula:

    4.8x10⁻²⁰ = [Cu²⁺] [1.26x10⁻⁴]²

    3.0x10⁻¹² = [Cu²⁺]

    That means the maximum amount of Cu²⁺ that can be in solution is 3.0x10⁻¹²M, thus, molar solubility of Cu (OH) ₂ is

    E) 3.0x10⁻¹²
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