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29 March, 09:44

How many grams of KNO3 will be required to prepare 800 mL of 1.4 M KNO3?

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  1. 29 March, 10:48
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    mass KNO3 = 113.236 g

    Explanation:

    ∴V sln = 800 mL = 0.800 L

    ∴ C KNO3sln = 1.4 M

    mass KNO3:

    ∴ molar mass KNO3 = 101.1032 g/mol

    ⇒ mol KNO3 = (0.800 L) * (1.4 mol/L) = 1.12 mol

    ⇒ mass KNO3 = (1.12 mol) * (101.1032 g/mol) = 113.236 g
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