What would the temperature of 0.734 moles of chlorine gas be at 1.83 atmospheres in a 10.2

liter container? (R = 0.0821 Latm/molk)

Answer: 310K

Explanation:

Given that:

Volume of Chlorine gas V = 10.2L

Temperature T = ?

Pressure P = 1.83 atm

Number of moles of chlorine gas N = 0.734 moles

Molar gas constant R is a constant with a value of 0.0821 atm L K-1 mol-1

Then, apply ideal gas equation

pV = nRT

1.83atm x 10.2L = 0.734 moles x 0.0821 atm L K-1 mol-1 x T

18.67atm L = 0.0603 atm L K-1 x T

T = (18.67atm L / 0.0603 atm L K-1)

T = 309.8K (Round up to 310K)

Thus, the temperature of the chlorine gas is 310 kelvin