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20 June, 01:47

An aqueous solution of cesium chloride is prepared by dissolving 52.3 g cesium chloride in 60.0g of water at 25°C. The volume of this solution is 63.3 mL. What is the molarity of the solution?

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  1. 20 June, 03:04
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    Given dа ta:

    Mass of cesium chloride CsCl (m) = 52.3 g

    Mass of water (mh2O) = 60.0 g

    Volume of the solution (V) = 63.3 ml

    Step 1: Calculate the number of moles of CsCl

    Molar mass of CsCl = 168.36 g/mol

    Mass of CsCl = 52.3 g

    # moles = mass/molar mass = 52.3 g/168.36 g. mol-1 = 0.3106 moles

    Step 2: Volume of solution in Liters

    1000 ml = 1 liter

    therefore, 63.3 ml corresponds to : 63.3 ml * 1 L/1000 ml = 0.0633 L

    Step 3: Calculate molarity of CsCl

    Molarity = moles of CsCl/volume of solution

    = 0.3106 moles/0.0633 L = 4.91 moles/L

    Molarity = 4.91 M
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