Ask Question
22 November, 18:52

calculate how many moles of NO2 form when each of the following completely reacts. 2N2O5 (g) →4NO2 (g) + O2 (g) Part A 1.0 mol N2O5 Express your answer using two significant figures. nothing mol m o l Request Answer Part B 5.4 mol N2O5 Express your answer using two significant figures.

+3
Answers (1)
  1. 22 November, 21:06
    0
    Part A: 2.0 mol.

    Part B: 10.8 mol.

    Explanation:

    For the balanced reaction:

    2N₂O₅ (g) → 4NO₂ (g) + O₂ (g),

    It is clear that 2 mol of N₂O₅ (g) dissociate to 4 mol of NO₂ (g) and 1 mol O₂ (g).

    Part A 1.0 mol N₂O₅:

    Using cross multiplication:

    2 mol of N₂O₅ (g) produces → 4 mol of NO₂ (g), from stichiometry.

    1 mol of N₂O₅ (g) produces →? mol of NO₂ (g),

    ∴ The no. of moles of NO₂ produced = (1 mol) (4 mol) / (2 mol) = 2.0 mol.

    Part B 5.4 mol N₂O₅:

    Using cross multiplication:

    2 mol of N₂O₅ (g) produces → 4 mol of NO₂ (g), from stichiometry.

    5.4 mol of N₂O₅ (g) produces →? mol of NO₂ (g),

    ∴ The no. of moles of NO₂ produced = (5.4 mol) (4 mol) / (2 mol) = 10.8 mol.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “calculate how many moles of NO2 form when each of the following completely reacts. 2N2O5 (g) →4NO2 (g) + O2 (g) Part A 1.0 mol N2O5 Express ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers