4. A compound composed of carbon, hydrogen, and chlorine effuses through a pinhole 0.411 times as fast as neon. Select the correct molecular formula for the compound. A. CHCl3 B. CH2Cl2 C. C2H2Cl2 D. C2H3Cl E. CCl4

Option A. CHCl3

Explanation:

Step 1:

Representation:

Let R1 be the rate of effusion of Neon.

Let R2 be the rate of effusion of the compound

Let M1 be the molar mass of Neon.

Let M2 be the molar mass of the compound

Step 2:

Data obtained from the question. This includes:

Rate of effusion of Ne (R1) = R1

Rate and effusion of the compound (R2) = 0.411 x R1

Molar Mass of Neon (M1) = 20. 18g/mol

Molar Mass of the compound (M2) = ?

Step 3:

Determination of the molar mass of the compound.

To obtain the formula of the compound, we need to determine the molar mass of the compound.

Applying the Graham's law of diffusion equation, the molar mass of the compound is obtained as follow:

R1/R2 = √ (M2/M1)

R1/0.411 x R1 = √ (M2/20.18)

1/0.411 = √ (M2/20.18)

Take the square of both sides.

(1/0.411) ^2 = M2/20.18

Cross multiply to express in linear form

M2 = (1/0.411) ^2 x20.18

M2 = 119.5g/mol

The molar mass of the compound is 119.5g/mol

Step 4:

Determination of the formula of the compound.

To know which option is correct, we'll simply evaluate the options as follows:

For option A:

Molar Mass of CHCl3 = 12 + 1 + (35.5x3) = 12 + 1 + 106.5 = 119.5g/mol

For option B:

Molar Mass of CH2Cl2 = 12 + (2x1) + (35.5x2) = 85g/mol

For option C.

Molar Mass of C2H2Cl2 = (12x2 + (2x1) + (35.5x2) = 97g/mol

For option D.

Molar Mass of C2H3Cl = (12x2) + (3x1) + 35.5 = 62.5g/mol

For option E.

Molar Mass of CCl4 = 12 + (35.5x4) =

154g/mol

From the above illustration, option A has the same molar mass as the compound. Therefore, option A is the correct answer.