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17 June, 02:39

How many ions form when 39 grams of calcium fluoride are added to excess water? a. 0.50 mol b. 1.0 mol c. 1.5 mol d. 3.0 mol

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Answers (2)
  1. 17 June, 04:00
    0
    1.5 mol ions
  2. 17 June, 05:17
    0
    c. 1.5 mol

    Explanation:

    Firstly, we need to calculate the no, of moles of 39.0 grams of calcium fluoride.

    n = mass / molar mass = (39.0 g) / (78.07 g/mol) = 0.499 mol ≅ 0.5 mol.

    CaF₂ ionized in water as:

    CaF₂ → Ca⁺² + 2F⁻.

    Every 0.1 mole of CaF₂ is ionized to 3 ions (1 ion of Ca⁺² and 2 ions of F⁻).

    So, 0.5 mol of CaF₂ will contain (3 x 0.5 mol = 1.5 mol) of ions.

    Thus, the right choice is "c. 1.5 mol".
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