During an experiment, a student spilt 1.0 mL of concentrated H2SO4. The student neutralized the acid with 3.05 g of NaHCO3. What is the concentration of H2SO4?

18.2 M

Explanation:

M (NaHCO3) = 23 + 1 + 12 + 3*16 = 84 g/mol

3.05 g * 1 mol/84 g = (3.05/84) mol NaHCO3

2NaHCO3 + H2SO4 - --> Na2SO4 + 2H2O + 2CO2

from reaction 2 mol 1 mol

given (3.05/84) mol x mol

x = (3.05/84) * 1/2 = (3.05/84) / 2 mol H2SO4

(3.05/84) / 2 mol H2SO4 - 0.001 L

x mol - 1 L

x = [ (3.05/84) * 1/2]/0.001 = 18 2 mol/L = 18.2 M H2SO4