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26 March, 12:11

What are the respective concentrations (m) of fe3 + and i - afforded by dissolving 0.200 mol fei3 in water and diluting to 725 ml?

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  1. 26 March, 13:00
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    Molarity = moles / liter of solution

    Given, Moles of Fe³⁺ = 0.200

    Volume of solution = 725 ml = 0.725 L

    Conversion factor: 1000 ml = 1L

    Molarity = 0.200 / 0.725 L = 0.275 M

    The dissociation of Fel₃ in water is ad follows:

    Fel₃ → Fe³⁺ + 3l⁻

    1 mole of Fel₃ gives 1 mole of Fe³⁺ ions and 3 moles of l⁻

    Since the solution is 0.275 M of Fel₃, so there are 0.275 M of Fe³⁺ ions,

    and (3 x 0.275 M) = 0.825 M of l⁻ ions.
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