At 450 mm Hg a gas has a volume of 760 L, what is its volume at standard pressure

450.0 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and T are constant, and have different values of P and V:

(P₁V₁) = (P₂V₂).

V₁ = 760.0 L, P₁ = 450.0 mm Hg,

V₂ = ? L, P₂ = 760.0 mm Hg (standard pressure = 1.0 atm = 760 mm Hg).

∴ V₂ = (P₁V₁) / (P₂) = (760.0 L) (450.0 mm Hg) / (760.0 mm Hg) = 450.0 L.