What volume of 0.175 m na3po4 solution is necessary to completely react with 95.4 ml of 0.102 m cucl2?

The volume of 0.175 M Na3PO4 solution that is necessary to completely react withn 95.4 ml of 0.102 M cuCl2 is

calculation

Step 1: write the equation for reaction

3CuCl2 (aq) + 2Na3Po4 → Cu3 (PO4) 2 + 6 NaCl

Step 2 : find the moles of CuCl2

moles = molarity x volume in liters

volume in liters = 95.4 / 1000 = 0.0954 L

moles is therefore = 0.0954 L x 0.102 M = 0.00973 moles

Step : use the mole ratio to calculate the moles of Na3Po4

The mole ratio of CuCl2 : Na3PO4 is 3:2 therefore = 0.00973 x2/3 = 0.00649 moles

Step 4 : find the volume of Na3PO4

volume = moles/molarity

= 0.00649 mole / 0.175=0.037 M