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14 November, 04:57

Calculate the standard entropy of reaction at 298 K for the reaction Hg (liq) + Cl2 (g) → HgCl2 (s) The standard molar entropies of the species at that temperature are: Sºm (Hg, liq) = 76.02 J / (K mol); Sºm (Cl2, g) = 223.07 J / (K mol); Sºm (HgCl2, s) = 146.0 J / (K mol)

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  1. 14 November, 07:02
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    -153.1 J / (K mol)

    Explanation:

    Calculate the standard entropy of reaction at 298 K for the reaction Hg (liq) + Cl2 (g) → HgCl2 (s) The standard molar entropies of the species at that temperature are: Sºm (Hg, liq) = 76.02 J / (K mol); Sºm (Cl2, g) = 223.07 J / (K mol); Sºm (HgCl2, s) = 146.0 J / (K mol)

    Hg (liq) + Cl2 (g) → HgCl2 (s)

    Given that;

    The standard molar entropies of the species at that temperature are:

    Sºm (Hg, liq) = 76.02 J / (K mol);

    Sºm (Cl2, g) = 223.07 J / (K mol);

    Sºm (HgCl2, s) = 146.0 J / (K mol)

    The standard molar entropies of reaction = Sºm[products] - Sºm [ reactants]

    = 146.0 J / (K mol) - [76.02 J / (K mol) + 223.07 J / (K mol) ]

    = - 153.09 J / (K mol)

    = or - 153.1 J / (K mol)

    Hence the answer is - 153.1 J / (K mol)
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