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6 September, 11:44

If a gas at 25oC occupies 3.60 L at a pressure of 2.50 atm, what will be its volume at a pressure of 1.00 atm if the temperature does NOT change?

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  1. 6 September, 13:05
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    9L

    Explanation:

    Given parameters:

    Initial volume V₁ = 3.6L

    Initial pressure P₁ = 2.5atm

    Final pressure P₂ = 1atm

    Unknown:

    Final volume V₂ = ?

    Condition: constant temperature = 25°C

    Solution:

    This problem compares the volume and pressure of a gas at constant temperature.

    This is highly synonymous to the postulate of Boyle's law. It states that "the volume of a fixed mass of gas is inversely proportional to the pressure provided that temperature is constant".

    Mathematically;

    P₁V₁ = P₂V₂

    where P and V are pressure and volume

    1 and 2 are initial and final states

    Input the parameters and solve for V₂;

    2.5 x 3.6 = 1 x V₂

    V₂ = 9L
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