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17 September, 02:50

What volume of 12.0 M sulfuric acid is needed to prepare 300.0 mL of 2.50 M solution?

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  1. 17 September, 03:33
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    n=c*V

    =2.50*300x10^-3

    =.75 moles of hcl

    v=n/c

    =.75/12

    =.0625 L

    convert to mL

    =62.5mL
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