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11 November, 08:34

The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant.

H2 (g) + Br2 (g) ⇌ 2 HBr (g) Kc = 3.8 * 104

4 HBr (g) ⇌ 2 H2 (g) + 2 Br2 (g) Kc = ?

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  1. 11 November, 09:04
    0
    To calculate Kc of the second step, we must observe the first reaction.

    If we rotate the first reaction and multiplay it by 2 we get the same thing.

    So the rotation means 1/kc (first reaction)

    And by multiplying it by 2, K should be squared.

    Kc2=1 / (kc1) ^2=6.92*10^-10
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