What is the mass (in grams) of 9.93 Ă - 1024 molecules of methanol (CH3OH) ?

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Chemistry

Ivan Olsen

29 October, 13:36

What is the mass (in grams) of 9.93 Ă - 1024 molecules of methanol (CH3OH) ?

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Buckley · Answer 1

Answer is: mass of methanol is 528.32 grams.

N (CH₃OH) = 9.93·10²⁴; number of methanol molecules.

n (CH₃OH) = N (CH₃OH) : Na (Avogadro constant).

n (CH₃OH) = 9.93·10²⁴ : 6.022·10²³ 1/mol.

n (CH₃OH) = 16.49 mol; amount of substance.

m (CH₃OH) = n (CH₃OH) · M (CH₃OH).

m (CH₃OH) = 16.49 mol · 32.04 g/mol.

m (CH₃OH) = 528.32 g.