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23 October, 19:46

Students working in lab use 52.3g of CaCl2 to make a solution. When the solution is brought to a final volume of 800. mL, what is the concentration?

A. 0.139 M

B. 0.153 M

C. 0.588 M

D. 0.632 M

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Answers (1)
  1. 23 October, 22:39
    0
    The answer is C:.588 M

    Explanation:

    [CaCl2] = mols CaCl2/Liters of solution

    molar mass of CaCl2 = 110.98 g / 1 mole (from periodic table)

    800 mL/1000 mL =.8 Liters of solution

    1)

    52.3g CaCl2 / 110.98g =.47 mole

    2)

    .47 mole/.8 L =.589 M

    So the answer is C
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