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16 March, 07:44

What mass of magnesium bromide is formed when 1.00 g of magnesium reacts with 5.00 g of bromine?

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  1. 16 March, 11:13
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    3.39g of MgBr

    Explanation:

    Reaction between magnesium and bromine

    Mg + Br₂ → MgBr

    Mass of MgBr = ?

    1g of Mg + 5.0g of Br₂

    6g of Mg and Br₂

    Molar mass of Mg = 24g/mol

    Molar mass of Br = 80g/mol

    Number of moles = mass / molar mass

    Mass = number of moles * molarmass

    Mass of Mg = 1 * 24 = 24g

    Mass of Br₂ = 1 * (2*80) = 160g (diatomic molecule)

    Molarmass of MgBr = (24 + 80) = 104g/mol

    Mass of MgBr = 1 * 104 = 104g/mol

    24g of Mg + 160g of Br₂ = 104g of MgBr

    184g of (mg and Br) = 104g of mgBr

    6g of (mg and Br) = y g of MgBr

    y = (6 * 104) / 184

    y = 3.39g of MgBr
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